Errata to Fundamentals of Machine Elements, B.J. Hamrock,
B.O. Jacobson, and S.R. Schmid, First Edition, First Printing.

p. 11,   line 4,   "component not" becomes 'component does not"

p. 25,   problem 1.7,     add "The weight of skier and equipment is 100 kg."

p. 36,   Eq. (b), "   becomes " ="

p. 41,   line 7,   "Eqs. (b) to (d) becomes "Eqs. (a) to (d)"

p. 52,   Fig. 2.15(b), flip shear stress arrows on right and left sides of square

p. 59,   line 5,   "=11.765" becomes "=11.715"

p. 62,   line 5,   "+ "    becomes " "

p. 62,   last line, "  " becomes "  "

p. 63,   second to last line, " " becomes "  "

p. 66,   line 9, "  " becomes "  " and " " becomes         " "

p. 70,   column 2, line 4, "-140" becomes "-36"

                             line 6, "43" becomes "96"

p. 71,   column 1, lines 8 and 9 "  as shown in Fig. 2.24(c)"  becomes    " "

p. 71,   column 2, last two lines, "stress is approximately the circle radius, or 122 "                      becomes "strain is approximately twice the circle radius, or 244 "

p. 78,   Sketch l, Sketch needs to be mirrored

p. 79,   problem 2.19, " " becomes " " and       " " becomes "

p. 79,   problem 2.20, " " becomes " =5 N/m

p. 82,   problem 2.31, " =4 kN/m" becomes " =6 kN/m and l=12 m"

p.84,    problem 2.47, add " The cross sectional area of the rod is 0.025 . "

p. 88,   problem 2.68,  "0.0001" becomes "-0.0001"

p. 88,   problem 2.69,   "0.005" becomes "0.0005"

p. 137,  problem 3.13, add "Neglect bending."

p. 153,  Example 4.7,   "=0.3144 GPa" becomes "Pa=0.3144 GPa"

p. 162,  9 lines from bottom, " and from " becomes " and negative from "

p. 175,  problem 4.2,    "cutous" becomes "cutouts"

p. 178,  problem 4.22, "0.05m" becomes "5 mm"

p. 191,  Figure 5.4 (c), " " becomes "M"

p. 193,  Table 5.1(b), "y = -" becomes "y ="

p. 196,  line above Eq. (5.18), "=dA" becomes "=A"

p. 206,  column 1, 8 lines from bottom, "20 ft" becomes "25 ft"

p. 207,  Figure 5.11 (c)  "U" becomes "P"

p. 212, problem 5.13,   "is no spring" becomes "is a spring" and

            "50 mm  occurs" becomes "50 mm occurs at the spring"

p. 214, problem 5.20, "deformation. Assume" becomes "deformations and their locations.          Assume"

p. 235,  5 lines from bottom, "titanium" becomes "platinum"

p. 240,  Fig. 6.13(a), flip arrow

p. 240,  Fig. 6.13(b), flip bottom arrow

p. 241,  Fig. 6.14(a), flip arrow

p. 241,  Fig 6.14(b), flip bottom arrow

p. 243,  Eq. (6.14), "+" becomes "-"

p. 245,  line6, "IFT" becomes "MNST" and line 7, "b" becomes "a"

p. 250, column 1, "+" becomes "-"

p. 254, sketch d, "5 mm" becomes "25 mm"

p. 254, problem 6.12, line 3 "crack" becomes "crack half-length"

p. 254, problem 6.14, line 1, "crack" becomes "crack half-length"

p. 255, problem 6.27, "free end, a 100-N" becomes "free end, a 1000-N force is in the x-direction, a 100-N"

p. 256, problem 6.30, line 1, "8 N-m" becomes "8 kN-m"

p. 263,  Table 7.1, "Fatigue strength      " becomes "Fracture strength "

p. 265, “S’_e = 0.29S_u” becomes “S’_e = 025 S_u”

p. 267,  Table 7.2 " " becomes "  "

p. 268, “S’_l = 0.72 S_u” becomes “S’_l = 0.45 S_u”

p. 269,  Example 7.2, line 4, "10,000" becomes "1000"

p. 282,  middle of page, delete the following sentence, "The Soderberg relationship is usually not recommended."

p. 286,  8 lines from bottom, " "becomes " "

p. 286,  6 lines from bottom,  " " becomes " "

p. 286,  5 lines from bottom, "= 2.427" becomes " = 2.110"

p. 286,  3 lines from bottom, " " becomes " "

p. 286,  2 lines from bottom, "4.820" becomes "3.438"

p. 296,  Fig. 7.16 caption,  "point 0" becomes "section A-A"

p. 299,  line 5,  "stress level that ensures failure due to fatigue" becomes "life until failure due to fatigue"

p. 301, problem 7.4, line 1, "c determine" becomes "c which are made of AISI 1040 steel and cold drawn determine"

p. 302, problem 7.7, line 1, "d=32" becomes d=33"

p. 303, problem 7.13, line 1, "5-mm" becomes "3-mm"

p. 304, problem 7.18, line 2,     "10/3" becomes "31/3"

p. 304, problem 7.19, line 1, "solid cross" becomes "solid circular cross"

p. 305, problem 7.25, line 3, "3600 N/m" becomes "3600 N/m per meter length. Thus one meter length of rope will have a spring constant of 3600 N/m"

p. 306, problem 7.28, line 7, "3cm" becomes "8 cm"

p. 316,  lines 8, "white" becomes "blue"

p. 320,  line 1, "in between" becomes "between the plates will"

p. 323,  Fig. 8.12, beginning of horizontal axis, "-50" becomes "-40" in two locations

p. 331,  Fig. 8.17, line 1, " interchange elliptical integral symbols "

p. 342,  3 lines from bottom, "Fig. 8.20" becomes "Fig. 8.21"

p. 378,  line 2, " =1604 " becomes " =1628 "

p. 378,  line 3, " 1604 " becomes " 1628 "

p. 395,  line before Eq. (10.14), " (B.49) " becomes " (B.58) "

p. 429,  line before Eq. 11.11, "if" becomes "if the von Mises stress [Eq. (6.10)]"

p. 429,  Eq. (11.11) "  " becomes "  "

p. 430,  Fig. 11.3 caption, "x-y " becomes "x-z " and "x-z  " becomes "x-y  "

p. 444,  last line, "rad s" becomes "rad/s"

p. 453,  2nd line of solution,  " lbm/in² " becomes " lbm/in³ "

p. 453,  7 lines from bottom, " 1.193 " becomes "1.187 "

p. 454,  line 4,  " " becomes "  " and " "     becomes "  "

p. 454,  line 12, becomes " "

p. 454,  line 13, becomes,  " "

p. 454, 7 lines from bottom becomes, "

p, 460, problem 11.2, line 2, "in an upward" becomes "in a 45° upward"

p. 462, problem 11.10, line 1, "7200" becomes "1000"

p. 462, problem 11.10, line 4, add "The shaft is made of annealed carbon steel with  "

p. 462, problem 11.11, "60mm" becomes "30 mm" and "1080" becomes "1030"

p. 464, problem 11.16, equation becomes "  "

p. 474,  9 lines from bottom, "Evidently the Couette terms" becomes "The Couette term"

p. 485,  After Eq. (12.52) add, "The largest   is obtained when  "    

p. 488,  line 7 "  " becomes "

p. 497,  10 lines from bottom, "  " becomes "  "

p. 497,  9 lines from bottom, " =16" becomes "=13"

p. 497,  6 lines from bottom, "  "

p. 497,  4 lines from bottom, "  "

p. 497,  3 lines from bottom,  "58°" becomes "55°" and "  " becomes " "                  

p. 497,  last line "  "

p. 498, line 1, "  "

p. 498,  line 4, "=17.0" becomes "=8.0"

p. 498,  line 6, "=12" becomes "=8.5"

p. 498,  line 7, "  "

p. 498,  line 9, "=18" becomes "=11"

p. 498,  line 10,

p. 498, line 12, "=0.88" becomes "=0.58"

p. 498,  line 13 becomes, "  "

p. 498,  line 14, becomes, "  "

p. 503, line 7, " "     becomes "  "

p. 503,  line 11, "  "

p. 503,  line 15, "  "

p. 509,  Fig. 12.18, right vertical axis,  "  " becomes "  "

p. 513,  last line becomes, "  "

p. 514,  1st equation becomes, "  "

p. 514,  2nd equation becomes, "  "

p. 514,  3rd equation becomes. "  "

p. 514,  4th equation becomes, "  "

p. 514,  line before Section 12.45, "21.5°" becomes "18°"

p. 520,  1st equation after Eq. (g), "  " becomes "  "

p. 528,  column 1, last line, " 66.34° " becomes " 62.38° "

p. 528,  column 2, line 3, "+66.34/2 = 233.2°F " becomes " + 62.38/2 = 231.2°F "

p. 528,  column 2, line 4, " 233.2°F " becomes " 231.2°F=110.9°C "

p. 528,  column 2, line 5,  "1.2" becomes "0.94"

p. 528,  column 2,  lines 8 becomes, "  "

p. 528,  column 2, line 10 becomes, " or

p. 531, problem 12.2, equation becomes, "  "

p. 531, problem 12.3, line 1,  "length" becomes "width"

p. 532, problem 12.8, line 3,  eliminate " position and"

p. 536, problem 12.20, line 3, after 100°C " add the following " The radial load per area is 1.5 MPa. "

p. 536, problem 12.24, line 3, "P" in two locations becomes "  "

p. 541,  10 lines from bottom, "13" becomes "12"

p. 582,  Eq. (13.64), "1.17" becomes "1.7"

p. 592,  Table 13.9, 1st column "  " in six locations becomes "  "

p. 605, problem 13.3, line 1, eliminate "214"

p. 605, problem 13.3, line 3, add the following " The static radial load capacity of the bearing is 36 920 N. Assume balls and rings are made of steel. "

p. 606, Sketch a, " 83 diam " should be to the bottom of inner ring raceway and not to the shoulder of inner ring.

p. 608, problem 13.14, line 2, after " load " add the following " per unit width "

p. 608, problem 13.17, line 2, eliminate material after " (NU202EC) "

p. 608, problem 13.17, lines 3 and 4, eliminate material after " (6309) "

p. 609, problem 13.18, line 2, add " at A " after NU 202EC

P. 609, problem 13.18, line 4, add " at B " after 6309

p. 610, problem 13.25, line 2, " at A " becomes " at 0 "

p. 610, problem 13.25, line 3, " at 0 " becomes " at A "

p. 611, problem 13.26, line 3, eliminate " P= "

p. 620,  Eq. (14.2), " Total width of gear " becomes " Tooth thickness "

p, 635, "The center distance for internally meshing spur gears is           (14.26) "

            becomes  "The length of the line of action for externally  meshing gears is obtained from Eq. (14.19). The changes necessary for determining the lines of action for internally  meshing gears are

                                                                      (14.26)

p. 648,  4 lines from bottom,  "     " in two locations should be "  "

p. 656,  column 1, 5 lines from bottom, " 0.25 " becomes " 0.23 "

p. 656,  column 2, line 1, add " For a pressure angle of 20°. "

p. 656,  column 2, line 7, " 25.9 " becomes  " 26.0 "

p. 658,  problem 14.2, line 2, " 39 " becomes " 32 "

p. 659,  problem 14.5, line 2, eliminate material after 25° to the end of the sentence.

p. 659,  problem 14.5, line 3, " 10-mm " becomes " 5-mm " and " 425 " becomes " 435 "

p. 660,  problem 14.10, line 2, add " and " after "20°," and eliminate material after "inch"  

              until the end of the sentence.

p. 660,  problem 14.11, lines 2 and 3, eliminate last three sentences.

p. 664,  problem 14.38, line 1, after "  " add "  "      

p. 670,  line 3, eliminate " square "

p. 671,  last two lines become "     (15.4)

            The equation to the left is valid only when inches are used for   while the equation to the right is valid only when millimeters are used for .

p. 675,  line 3, "  " becomes "  "

p. 684,  Eq. (15.24), eliminate " 2 " Also in two locations " L_i" becomes  "2L_i"

p. 684,  Eq.(15.26), eliminate " " and "  " becomes "  "

p. 685, 6 lines from bottom, eliminate 2,  also " 25 " becomes " 50 " in two locations and " 33.93 " becomes " 50.86 "

p. 685, 5 lines from bottom, eliminate 2, also " 2.5 " becomes " 5 " in two locations and " 527.1 " becomes " 543.1 "

p. 685, 4 lines from bottom, eliminate 2, also " 27.5 " becomes " 55 " in two locations, 

             and " 11.13 " becomes " 16.92 "

p. 685,  last two lines becomes "  "

p. 686,  line 6,  " 2.5 " becomes " 30 "

p. 686,  line 7,  " 282.4 " becomes " 10.67 "

p. 686,  lines 8, 9, and 10, eliminate these lines

p. 686,  lines 12, 13, and 14 become "

                                                                    =

p. 686,  line 15, eliminate " quite "

p. 686,  line 19, "

p. 721,  problem 15.1, line 1, " pitch " becomes " crest " and "1 in." becomes   in. " 

p. 721,  problem 15.1, line 4, " Crest " becomes " Pitch "

p. 721,  problem 15.1, line 6, " needed " becomes " allowed "

p. 723,  problem 15.9, line 2, "1750 W" becomes "1750 W per screw"

p. 732,  problem 15.29, line 4, eliminate  from after " 3.0 till end of sentence "

p. 739,  line above Eq. (16.3), eliminate " from Eq. (3.14) "

p. 739, Eq. (16.3),  " " becomes "  "

p. 747,  Fig. 16.5(b), " " becomes " "

p. 750,  after equation (c), on the next line add "  "

p. 750  11 lines from bottom, "0.7935" becomes "0. 7929"

p. 750,  9 lines from bottom, " 0.7935 " becomes " 0.7929 "

p. 751,  line 7 becomes,  "  "

p. 751,  line 12 becomes, "  "

p. 751,  line 13 becomes, "  "

p. 751,  line 15 becomes, "  "

p. 751,  line 17 becomes, "  "

p. 751,  line 18 becomes, " "

p. 767,  line 4 becomes, "

p. 771,  column 1, last line, " 61" becomes " 47.4 "

p. 771,  column 2, line 2, " 34 " becomes " 24.31" and " 16 " becomes " 11.9 "

p. 776,  problem 16.14, line 1, before " made " add " with plain ends "

p. 776,  problem 16.15, line 1 " 18 mm- " becomes " 18 mm-mean "

p. 776,  problem 16.16, line 1 " mm " becomes " mm-mean " also after " spring " add       "with plain ends "

p. 776,  problem 16.16, line 3, after " coils " add " Free length is 500 mm. "

p. 776,  problem 16.17, line 4, " tension " becomes " torsion "

p. 778,  problem 16.23, " BS 5216 " becomes " hard drawn "

p. 786,  5 lines down from Eq. (17.16),  " a larger " becomes " a smaller "

p. 786,  7 lines down from Eq. (17.16), eliminate entire line

p. 806,   line 1, "  " becomes " "

p. 813,  column 2, 1st equation, " 60 000 " becomes " 66 100 "

p. 813,  column 2, line after 1st equation " 540 000 " becomes " 595 000 "

p. 813,   column 2, equation middle of column " 270 000 " becomes " 297 500 "

p. 813,   column 2, last two lines, " 270 000 " becomes " 297 500 " and " 240.6 " becomes " 265.1"

p. 814,  column 1, line 5 " 895 500 " becomes " 988 900 "

p. 814,  column 1, line 7 " 270 000 " becomes " 297 500 "

p. 814,  column 2, line 1, " 20 700 " becomes " 22 810 "

p. 817,   problem 17.9, line 2, " 1.8 " becomes " 1.8 for maximum pressure "

p. 817,   problem 17.9, line 3, " actuating " becomes " normal "

p. 820,   problem 17.21, line 6, add "The coefficient of friction is 0.29.

p. 834,   Eq. (18.11), "  "

p. 846,   3 lines f